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68=2-2(5x-3)
We move all terms to the left:
68-(2-2(5x-3))=0
We calculate terms in parentheses: -(2-2(5x-3)), so:We get rid of parentheses
2-2(5x-3)
determiningTheFunctionDomain -2(5x-3)+2
We multiply parentheses
-10x+6+2
We add all the numbers together, and all the variables
-10x+8
Back to the equation:
-(-10x+8)
10x-8+68=0
We add all the numbers together, and all the variables
10x+60=0
We move all terms containing x to the left, all other terms to the right
10x=-60
x=-60/10
x=-6
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