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68=1/5+(20x+50)+2
We move all terms to the left:
68-(1/5+(20x+50)+2)=0
Domain of the equation: 5+(20x+50)+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
(20x+50)+2)!=-5
x∈R
-(1+68*5+(20x+50)+2)=0
We calculate terms in parentheses: -(1+68*5+(20x+50)+2), so:We get rid of parentheses
1+68*5+(20x+50)+2
determiningTheFunctionDomain (20x+50)+1+2+68*5
We add all the numbers together, and all the variables
(20x+50)+343
We get rid of parentheses
20x+50+343
We add all the numbers together, and all the variables
20x+393
Back to the equation:
-(20x+393)
-20x-393=0
We move all terms containing x to the left, all other terms to the right
-20x=393
x=393/-20
x=-19+13/20
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