68=1/5(20x+50)+20

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Solution for 68=1/5(20x+50)+20 equation: 



68=1/5(20x+50)+20

We move all terms to the left:

68-(1/5(20x+50)+20)=0



Domain of the equation: 5(20x+50)+20)!=0

x∈R



We multiply all the terms by the denominator


-(1+68*5(20x+50)+20)=0



We calculate terms in parentheses: -(1+68*5(20x+50)+20), so:

1+68*5(20x+50)+20

determiningTheFunctionDomain
68*5(20x+50)+1+20

We add all the numbers together, and all the variables

68*5(20x+50)+21

Wy multiply elements

340x(2+21

Back to the equation:

-(340x(2+21)



We add all the numbers together, and all the variables

-(340x23=0

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