68=1/3(20x+50)=2

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Solution for 68=1/3(20x+50)=2 equation: 



68=1/3(20x+50)=2

We move all terms to the left:

68-(1/3(20x+50))=0



Domain of the equation: 3(20x+50))!=0

x∈R



We multiply all the terms by the denominator


-(1+68*3(20x+50))=0



We calculate terms in parentheses: -(1+68*3(20x+50)), so:

1+68*3(20x+50)

determiningTheFunctionDomain
68*3(20x+50)+1

Wy multiply elements

204x(2+1

Back to the equation:

-(204x(2+1)



We add all the numbers together, and all the variables

-(204x3=0

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