68-(6x+4)=6(x+2)+x

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Solution for 68-(6x+4)=6(x+2)+x equation: 



68-(6x+4)=6(x+2)+x

We move all terms to the left:

68-(6x+4)-(6(x+2)+x)=0

We get rid of parentheses

-6x-(6(x+2)+x)-4+68=0



We calculate terms in parentheses: -(6(x+2)+x), so:

6(x+2)+x

We add all the numbers together, and all the variables

x+6(x+2)

We multiply parentheses

x+6x+12

We add all the numbers together, and all the variables

7x+12

Back to the equation:

-(7x+12)



We add all the numbers together, and all the variables

-6x-(7x+12)+64=0

We get rid of parentheses

-6x-7x-12+64=0

We add all the numbers together, and all the variables

-13x+52=0

We move all terms containing x to the left, all other terms to the right

-13x=-52

x=-52/-13

x=+4

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