67x-3x+7=3(x-4)+20

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Solution for 67x-3x+7=3(x-4)+20 equation: 



67x-3x+7=3(x-4)+20

We move all terms to the left:

67x-3x+7-(3(x-4)+20)=0

We add all the numbers together, and all the variables

64x-(3(x-4)+20)+7=0



We calculate terms in parentheses: -(3(x-4)+20), so:

3(x-4)+20

We multiply parentheses

3x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We get rid of parentheses

64x-3x-8+7=0

We add all the numbers together, and all the variables

61x-1=0

We move all terms containing x to the left, all other terms to the right

61x=1

x=1/61

x=1/61

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