67=4x-3(1+6x)

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Solution for 67=4x-3(1+6x) equation:



67=4x-3(1+6x)
We move all terms to the left:
67-(4x-3(1+6x))=0
We add all the numbers together, and all the variables
-(4x-3(6x+1))+67=0
We calculate terms in parentheses: -(4x-3(6x+1)), so:
4x-3(6x+1)
We multiply parentheses
4x-18x-3
We add all the numbers together, and all the variables
-14x-3
Back to the equation:
-(-14x-3)
We get rid of parentheses
14x+3+67=0
We add all the numbers together, and all the variables
14x+70=0
We move all terms containing x to the left, all other terms to the right
14x=-70
x=-70/14
x=-5

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