67+2(2X)(x=4)

Solution for 67+2(2X)(x=4) equation:

67+2(2X)(X=4)

We move all terms to the left:

67+2(2X)(X-(4))=0

We multiply parentheses

22X^2-88X+67=0

a = 22; b = -88; c = +67;
Δ = b2-4ac
Δ = -882-4·22·67
Δ = 1848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1848}=\sqrt{4*462}=\sqrt{4}*\sqrt{462}=2\sqrt{462}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-2\sqrt{462}}{2*22}=\frac{88-2\sqrt{462}}{44}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+2\sqrt{462}}{2*22}=\frac{88+2\sqrt{462}}{44}
$