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66x=24-18x^2
We move all terms to the left:
66x-(24-18x^2)=0
We get rid of parentheses
18x^2+66x-24=0
a = 18; b = 66; c = -24;
Δ = b2-4ac
Δ = 662-4·18·(-24)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-78}{2*18}=\frac{-144}{36} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+78}{2*18}=\frac{12}{36} =1/3 $
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