66=1/2(1x+5+3x+1)6

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Solution for 66=1/2(1x+5+3x+1)6 equation: 



66=1/2(1x+5+3x+1)6

We move all terms to the left:

66-(1/2(1x+5+3x+1)6)=0



Domain of the equation: 2(1x+5+3x+1)6)!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(4x+6)6)+66=0

We multiply all the terms by the denominator


-(1+66*2(4x+6)6)=0



We calculate terms in parentheses: -(1+66*2(4x+6)6), so:

1+66*2(4x+6)6

determiningTheFunctionDomain
66*2(4x+6)6+1

Wy multiply elements

132x(4+1

Back to the equation:

-(132x(4+1)



We add all the numbers together, and all the variables

-(132x5=0

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