66=(2(b+10))+b

Solution for 66=(2(b+10))+b equation:

66=(2(b+10))+b

We move all terms to the left:

66-((2(b+10))+b)=0


We calculate terms in parentheses: -((2(b+10))+b), so:

(2(b+10))+b

We add all the numbers together, and all the variables

b+(2(b+10))


We calculate terms in parentheses: +(2(b+10)), so:

2(b+10)

We multiply parentheses

2b+20

Back to the equation:

+(2b+20)


We get rid of parentheses

b+2b+20

We add all the numbers together, and all the variables

3b+20

Back to the equation:

-(3b+20)


We get rid of parentheses

-3b-20+66=0

We add all the numbers together, and all the variables

-3b+46=0

We move all terms containing b to the left, all other terms to the right

-3b=-46

b=-46/-3

b=15+1/3