66-(6x+3)=6(x+4)+x

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Solution for 66-(6x+3)=6(x+4)+x equation: 



66-(6x+3)=6(x+4)+x

We move all terms to the left:

66-(6x+3)-(6(x+4)+x)=0

We get rid of parentheses

-6x-(6(x+4)+x)-3+66=0



We calculate terms in parentheses: -(6(x+4)+x), so:

6(x+4)+x

We add all the numbers together, and all the variables

x+6(x+4)

We multiply parentheses

x+6x+24

We add all the numbers together, and all the variables

7x+24

Back to the equation:

-(7x+24)



We add all the numbers together, and all the variables

-6x-(7x+24)+63=0

We get rid of parentheses

-6x-7x-24+63=0

We add all the numbers together, and all the variables

-13x+39=0

We move all terms containing x to the left, all other terms to the right

-13x=-39

x=-39/-13

x=+3

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