65=2(n-4)-5(1+3n)

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Solution for 65=2(n-4)-5(1+3n) equation: 



65=2(n-4)-5(1+3n)

We move all terms to the left:

65-(2(n-4)-5(1+3n))=0

We add all the numbers together, and all the variables

-(2(n-4)-5(3n+1))+65=0



We calculate terms in parentheses: -(2(n-4)-5(3n+1)), so:

2(n-4)-5(3n+1)

We multiply parentheses

2n-15n-8-5

We add all the numbers together, and all the variables

-13n-13

Back to the equation:

-(-13n-13)



We get rid of parentheses

13n+13+65=0

We add all the numbers together, and all the variables

13n+78=0

We move all terms containing n to the left, all other terms to the right

13n=-78

n=-78/13

n=-6

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