65=2(3(1/4)x+1)+2(2x)

Solution for 65=2(3(1/4)x+1)+2(2x) equation:

65=2(3(1/4)x+1)+2(2x)

We move all terms to the left:

65-(2(3(1/4)x+1)+2(2x))=0


Domain of the equation: 4)x+1)+22x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(2(3(+1/4)x+1)+22x)+65=0

We multiply all the terms by the denominator


-(2(3(+1+65*4)x+1)+22x)=0


We calculate terms in parentheses: -(2(3(+1+65*4)x+1)+22x), so:

2(3(+1+65*4)x+1)+22x

We add all the numbers together, and all the variables

2(3261x+1)+22x

We add all the numbers together, and all the variables

22x+2(3261x+1)

We multiply parentheses

22x+6522x+2

We add all the numbers together, and all the variables

6544x+2

Back to the equation:

-(6544x+2)


We get rid of parentheses

-6544x-2=0

We move all terms containing x to the left, all other terms to the right

-6544x=2

x=2/-6544

x=-1/3272