65=14x2

Solution for 65=14x2 equation:

65=14x^2

We move all terms to the left:

65-(14x^2)=0

a = -14; b = 0; c = +65;
Δ = b2-4ac
Δ = 02-4·(-14)·65
Δ = 3640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3640}=\sqrt{4*910}=\sqrt{4}*\sqrt{910}=2\sqrt{910}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{910}}{2*-14}=\frac{0-2\sqrt{910}}{-28}
=-\frac{2\sqrt{910}}{-28}
=-\frac{\sqrt{910}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{910}}{2*-14}=\frac{0+2\sqrt{910}}{-28}
=\frac{2\sqrt{910}}{-28}
=\frac{\sqrt{910}}{-14}
$