65=1/5(325-4e)

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Solution for 65=1/5(325-4e) equation: 



65=1/5(325-4e)

We move all terms to the left:

65-(1/5(325-4e))=0



Domain of the equation: 5(325-4e))!=0

e∈R



We add all the numbers together, and all the variables

-(1/5(-4e+325))+65=0

We multiply all the terms by the denominator


-(1+65*5(-4e+325))=0



We calculate terms in parentheses: -(1+65*5(-4e+325)), so:

1+65*5(-4e+325)

determiningTheFunctionDomain
65*5(-4e+325)+1

Wy multiply elements

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We use the square of the difference formula

325e(-1

Back to the equation:

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