65=-3(-n-5)+8(n-2)

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Solution for 65=-3(-n-5)+8(n-2) equation: 



65=-3(-n-5)+8(n-2)

We move all terms to the left:

65-(-3(-n-5)+8(n-2))=0

We add all the numbers together, and all the variables

-(-3(-1n-5)+8(n-2))+65=0



We calculate terms in parentheses: -(-3(-1n-5)+8(n-2)), so:

-3(-1n-5)+8(n-2)

We multiply parentheses

3n+8n+15-16

We add all the numbers together, and all the variables

11n-1

Back to the equation:

-(11n-1)



We get rid of parentheses

-11n+1+65=0

We add all the numbers together, and all the variables

-11n+66=0

We move all terms containing n to the left, all other terms to the right

-11n=-66

n=-66/-11

n=+6

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