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65-t=(2)/(3)t
We move all terms to the left:
65-t-((2)/(3)t)=0
Domain of the equation: 3t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
-t-(+2/3t)+65=0
We add all the numbers together, and all the variables
-1t-(+2/3t)+65=0
We get rid of parentheses
-1t-2/3t+65=0
We multiply all the terms by the denominator
-1t*3t+65*3t-2=0
Wy multiply elements
-3t^2+195t-2=0
a = -3; b = 195; c = -2;
Δ = b2-4ac
Δ = 1952-4·(-3)·(-2)
Δ = 38001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-\sqrt{38001}}{2*-3}=\frac{-195-\sqrt{38001}}{-6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+\sqrt{38001}}{2*-3}=\frac{-195+\sqrt{38001}}{-6} $
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