65+5x=4(-x+3)-19

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Solution for 65+5x=4(-x+3)-19 equation: 



65+5x=4(-x+3)-19

We move all terms to the left:

65+5x-(4(-x+3)-19)=0

We add all the numbers together, and all the variables

5x-(4(-1x+3)-19)+65=0



We calculate terms in parentheses: -(4(-1x+3)-19), so:

4(-1x+3)-19

We multiply parentheses

-4x+12-19

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We get rid of parentheses

5x+4x+7+65=0

We add all the numbers together, and all the variables

9x+72=0

We move all terms containing x to the left, all other terms to the right

9x=-72

x=-72/9

x=-8

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