64=4(2+2b)-7(5b-8)

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Solution for 64=4(2+2b)-7(5b-8) equation:


Simplifying
64 = 4(2 + 2b) + -7(5b + -8)
64 = (2 * 4 + 2b * 4) + -7(5b + -8)
64 = (8 + 8b) + -7(5b + -8)

Reorder the terms:
64 = 8 + 8b + -7(-8 + 5b)
64 = 8 + 8b + (-8 * -7 + 5b * -7)
64 = 8 + 8b + (56 + -35b)

Reorder the terms:
64 = 8 + 56 + 8b + -35b

Combine like terms: 8 + 56 = 64
64 = 64 + 8b + -35b

Combine like terms: 8b + -35b = -27b
64 = 64 + -27b

Add '-64' to each side of the equation.
64 + -64 = 64 + -64 + -27b

Combine like terms: 64 + -64 = 0
0 = 64 + -64 + -27b

Combine like terms: 64 + -64 = 0
0 = 0 + -27b
0 = -27b

Solving
0 = -27b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '27b' to each side of the equation.
0 + 27b = -27b + 27b
Remove the zero:
27b = -27b + 27b

Combine like terms: -27b + 27b = 0
27b = 0

Divide each side by '27'.
b = 0

Simplifying
b = 0

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