64=(x+26)+(19x-2)

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Solution for 64=(x+26)+(19x-2) equation: 



64=(x+26)+(19x-2)

We move all terms to the left:

64-((x+26)+(19x-2))=0



We calculate terms in parentheses: -((x+26)+(19x-2)), so:

(x+26)+(19x-2)

We get rid of parentheses

x+19x+26-2

We add all the numbers together, and all the variables

20x+24

Back to the equation:

-(20x+24)



We get rid of parentheses

-20x-24+64=0

We add all the numbers together, and all the variables

-20x+40=0

We move all terms containing x to the left, all other terms to the right

-20x=-40

x=-40/-20

x=+2

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