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64+(4(3y+2))=180
We move all terms to the left:
64+(4(3y+2))-(180)=0
We add all the numbers together, and all the variables
(4(3y+2))-116=0
We calculate terms in parentheses: +(4(3y+2)), so:We get rid of parentheses
4(3y+2)
We multiply parentheses
12y+8
Back to the equation:
+(12y+8)
12y+8-116=0
We add all the numbers together, and all the variables
12y-108=0
We move all terms containing y to the left, all other terms to the right
12y=108
y=108/12
y=9
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