63x2=49+14

Solution for 63x2=49+14 equation:

63x^2=49+14

We move all terms to the left:

63x^2-(49+14)=0

We add all the numbers together, and all the variables

63x^2-63=0

a = 63; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·63·(-63)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*63}=\frac{-126}{126}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*63}=\frac{126}{126}
=1
$