If it's not what You are looking for type in the equation solver your own equation and let us solve it.
63=7(c+2)
We move all terms to the left:
63-(7(c+2))=0
We calculate terms in parentheses: -(7(c+2)), so:We get rid of parentheses
7(c+2)
We multiply parentheses
7c+14
Back to the equation:
-(7c+14)
-7c-14+63=0
We add all the numbers together, and all the variables
-7c+49=0
We move all terms containing c to the left, all other terms to the right
-7c=-49
c=-49/-7
c=+7
| c+4/4=3 | | r-70/3=5 | | -3x+3(-x-8)=18 | | 9(-12u+1)−9=6u | | 16/j=4 | | 8(j-92)=56 | | 8b^2-144=-24b | | 77=7d | | -3x=3(-x-8)=18 | | 6(4x+1-(78)=0 | | -6(8r+10)=-3(16r+20) | | 3(4–2x)=-2x | | 21+2y=39 | | 15x-6+2=36 | | 8x-2x+60=8x+32 | | h/9+-43=-49 | | (4/3)^2n=0 | | -7x-5(-3x+2)=54 | | -17r-7=25r-7(6r-7) | | q-17/8=10 | | (4/3)^2n=(16/15) | | 40=5w+3w | | 45=-5(-9+x) | | 25=7+6c | | 5v^2+23=-12 | | (x/3)-(x-3)/7=3 | | 23-2z=21 | | 25=12x-7 | | 26x+1=313 | | -182+15x=166+3x | | c/3+9=10 | | |z-7|=4 |