63=7(1+4x)

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Solution for 63=7(1+4x) equation: 



63=7(1+4x)

We move all terms to the left:

63-(7(1+4x))=0

We add all the numbers together, and all the variables

-(7(4x+1))+63=0



We calculate terms in parentheses: -(7(4x+1)), so:

7(4x+1)

We multiply parentheses

28x+7

Back to the equation:

-(28x+7)



We get rid of parentheses

-28x-7+63=0

We add all the numbers together, and all the variables

-28x+56=0

We move all terms containing x to the left, all other terms to the right

-28x=-56

x=-56/-28

x=+2

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