63=1/2(6)(b1+b2)

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Solution for 63=1/2(6)(b1+b2) equation: 



63=1/2(6)(b1+b2)

We move all terms to the left:

63-(1/2(6)(b1+b2))=0



Domain of the equation: 26(b1+b2))!=0

b∈R



We add all the numbers together, and all the variables

-(1/26(+b+b^2))+63=0

We multiply all the terms by the denominator


-(1+63*26(+b+b^2))=0



We calculate terms in parentheses: -(1+63*26(+b+b^2)), so:

1+63*26(+b+b^2)

determiningTheFunctionDomain
63*26(+b+b^2)+1

Wy multiply elements

1638b(++1

We use the square of the difference formula

1638b(+1

Back to the equation:

-(1638b(+1)



We add all the numbers together, and all the variables

-(1638b1=0

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