63=(1+4b)

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Solution for 63=(1+4b) equation: 



63=(1+4b)

We move all terms to the left:

63-((1+4b))=0

We add all the numbers together, and all the variables

-((4b+1))+63=0



We calculate terms in parentheses: -((4b+1)), so:

(4b+1)

We get rid of parentheses

4b+1

Back to the equation:

-(4b+1)



We get rid of parentheses

-4b-1+63=0

We add all the numbers together, and all the variables

-4b+62=0

We move all terms containing b to the left, all other terms to the right

-4b=-62

b=-62/-4

b=15+1/2

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