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62=5+3(1+3x)
We move all terms to the left:
62-(5+3(1+3x))=0
We add all the numbers together, and all the variables
-(5+3(3x+1))+62=0
We calculate terms in parentheses: -(5+3(3x+1)), so:We get rid of parentheses
5+3(3x+1)
determiningTheFunctionDomain 3(3x+1)+5
We multiply parentheses
9x+3+5
We add all the numbers together, and all the variables
9x+8
Back to the equation:
-(9x+8)
-9x-8+62=0
We add all the numbers together, and all the variables
-9x+54=0
We move all terms containing x to the left, all other terms to the right
-9x=-54
x=-54/-9
x=+6
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