62/3f-5=5

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Solution for 62/3f-5=5 equation: 



62/3f-5=5

We move all terms to the left:

62/3f-5-(5)=0



Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R



We add all the numbers together, and all the variables

62/3f-10=0

We multiply all the terms by the denominator


-10*3f+62=0

Wy multiply elements

-30f+62=0

We move all terms containing f to the left, all other terms to the right

-30f=-62

f=-62/-30

f=2+1/15

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