60x-12=7x(2x+2)

Solution for 60x-12=7x(2x+2) equation:

60x-12=7x(2x+2)

We move all terms to the left:

60x-12-(7x(2x+2))=0


We calculate terms in parentheses: -(7x(2x+2)), so:

7x(2x+2)

We multiply parentheses

14x^2+14x

Back to the equation:

-(14x^2+14x)


We get rid of parentheses

-14x^2+60x-14x-12=0

We add all the numbers together, and all the variables

-14x^2+46x-12=0

a = -14; b = 46; c = -12;
Δ = b2-4ac
Δ = 462-4·(-14)·(-12)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-38}{2*-14}=\frac{-84}{-28}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+38}{2*-14}=\frac{-8}{-28}
=2/7
$