60=4(k+3)+2(k+3)

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Solution for 60=4(k+3)+2(k+3) equation: 



60=4(k+3)+2(k+3)

We move all terms to the left:

60-(4(k+3)+2(k+3))=0



We calculate terms in parentheses: -(4(k+3)+2(k+3)), so:

4(k+3)+2(k+3)

We multiply parentheses

4k+2k+12+6

We add all the numbers together, and all the variables

6k+18

Back to the equation:

-(6k+18)



We get rid of parentheses

-6k-18+60=0

We add all the numbers together, and all the variables

-6k+42=0

We move all terms containing k to the left, all other terms to the right

-6k=-42

k=-42/-6

k=+7

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