60=2(z-58)

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Solution for 60=2(z-58) equation: 



60=2(z-58)

We move all terms to the left:

60-(2(z-58))=0



We calculate terms in parentheses: -(2(z-58)), so:

2(z-58)

We multiply parentheses

2z-116

Back to the equation:

-(2z-116)



We get rid of parentheses

-2z+116+60=0

We add all the numbers together, and all the variables

-2z+176=0

We move all terms containing z to the left, all other terms to the right

-2z=-176

z=-176/-2

z=+88

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