60=1/2(x+5)(3x+6)

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Solution for 60=1/2(x+5)(3x+6) equation: 



60=1/2(x+5)(3x+6)

We move all terms to the left:

60-(1/2(x+5)(3x+6))=0



Domain of the equation: 2(x+5)(3x+6))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+6x+15x+30))+60=0

We multiply all the terms by the denominator


-(1+60*2(+3x^2+6x+15x+30))=0



We calculate terms in parentheses: -(1+60*2(+3x^2+6x+15x+30)), so:

1+60*2(+3x^2+6x+15x+30)

determiningTheFunctionDomain
60*2(+3x^2+6x+15x+30)+1

Wy multiply elements

120x(++1

We use the square of the difference formula

120x(+1

Back to the equation:

-(120x(+1)



We add all the numbers together, and all the variables

-(120x1=0

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