60=(x+3)(3x+1)

Solution for 60=(x+3)(3x+1) equation:

60=(x+3)(3x+1)

We move all terms to the left:

60-((x+3)(3x+1))=0

We multiply parentheses ..

-((+3x^2+x+9x+3))+60=0


We calculate terms in parentheses: -((+3x^2+x+9x+3)), so:

(+3x^2+x+9x+3)

We get rid of parentheses

3x^2+x+9x+3

We add all the numbers together, and all the variables

3x^2+10x+3

Back to the equation:

-(3x^2+10x+3)


We get rid of parentheses

-3x^2-10x-3+60=0

We add all the numbers together, and all the variables

-3x^2-10x+57=0

a = -3; b = -10; c = +57;
Δ = b2-4ac
Δ = -102-4·(-3)·57
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-28}{2*-3}=\frac{-18}{-6}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+28}{2*-3}=\frac{38}{-6}
=-6+1/3
$