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600=x+2/3x
We move all terms to the left:
600-(x+2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+2/3x)+600=0
We get rid of parentheses
-x-2/3x+600=0
We multiply all the terms by the denominator
-x*3x+600*3x-2=0
Wy multiply elements
-3x^2+1800x-2=0
a = -3; b = 1800; c = -2;
Δ = b2-4ac
Δ = 18002-4·(-3)·(-2)
Δ = 3239976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3239976}=\sqrt{4*809994}=\sqrt{4}*\sqrt{809994}=2\sqrt{809994}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1800)-2\sqrt{809994}}{2*-3}=\frac{-1800-2\sqrt{809994}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1800)+2\sqrt{809994}}{2*-3}=\frac{-1800+2\sqrt{809994}}{-6} $
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