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6000=(w+40)w
We move all terms to the left:
6000-((w+40)w)=0
We calculate terms in parentheses: -((w+40)w), so:We get rid of parentheses
(w+40)w
We multiply parentheses
w^2+40w
Back to the equation:
-(w^2+40w)
-w^2-40w+6000=0
We add all the numbers together, and all the variables
-1w^2-40w+6000=0
a = -1; b = -40; c = +6000;
Δ = b2-4ac
Δ = -402-4·(-1)·6000
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-160}{2*-1}=\frac{-120}{-2} =+60 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+160}{2*-1}=\frac{200}{-2} =-100 $
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