600+800x-800x^2=0

Solution for 600+800x-800x^2=0 equation:

600+800x-800x^2=0

a = -800; b = 800; c = +600;
Δ = b2-4ac
Δ = 8002-4·(-800)·600
Δ = 2560000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2560000}=1600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-1600}{2*-800}=\frac{-2400}{-1600}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+1600}{2*-800}=\frac{800}{-1600}
=-1/2
$