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(60/5)*(2*x-5) = 0
12*(2*x-5) = 0
( 12 )
12 = 0
x belongs to the empty set
( 2*x-5 )
2*x-5 = 0 // + 5
2*x = 5 // : 2
x = 5/2
x = 5/2
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