60/4x-26=38/2x-1

Solution for 60/4x-26=38/2x-1 equation:

60/4x-26=38/2x-1

We move all terms to the left:

60/4x-26-(38/2x-1)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x-1)!=0

x∈R


We get rid of parentheses

60/4x-38/2x+1-26=0

We calculate fractions


120x/8x^2+(-152x)/8x^2+1-26=0

We add all the numbers together, and all the variables

120x/8x^2+(-152x)/8x^2-25=0

We multiply all the terms by the denominator


120x+(-152x)-25*8x^2=0

Wy multiply elements

-200x^2+120x+(-152x)=0

We get rid of parentheses

-200x^2+120x-152x=0

We add all the numbers together, and all the variables

-200x^2-32x=0

a = -200; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·(-200)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*-200}=\frac{0}{-400}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*-200}=\frac{64}{-400}
=-4/25
$