60-(4x+12)=4(x+3)+x

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Solution for 60-(4x+12)=4(x+3)+x equation: 



60-(4x+12)=4(x+3)+x

We move all terms to the left:

60-(4x+12)-(4(x+3)+x)=0

We get rid of parentheses

-4x-(4(x+3)+x)-12+60=0



We calculate terms in parentheses: -(4(x+3)+x), so:

4(x+3)+x

We add all the numbers together, and all the variables

x+4(x+3)

We multiply parentheses

x+4x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

-4x-(5x+12)+48=0

We get rid of parentheses

-4x-5x-12+48=0

We add all the numbers together, and all the variables

-9x+36=0

We move all terms containing x to the left, all other terms to the right

-9x=-36

x=-36/-9

x=+4

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