6/z-8/z

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Solution for 6/z-8/z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

6/z-(8/z) = 0

6/z-8*z^-1 = 0

-2*z^-1 = 0 // : -2

z^-1 = 0

z należy do O

z belongs to the empty set

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