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6/x=9/7x+9
We move all terms to the left:
6/x-(9/7x+9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 7x+9)!=0We get rid of parentheses
x∈R
6/x-9/7x-9=0
We calculate fractions
42x/7x^2+(-9x)/7x^2-9=0
We multiply all the terms by the denominator
42x+(-9x)-9*7x^2=0
Wy multiply elements
-63x^2+42x+(-9x)=0
We get rid of parentheses
-63x^2+42x-9x=0
We add all the numbers together, and all the variables
-63x^2+33x=0
a = -63; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-63)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-63}=\frac{-66}{-126} =11/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-63}=\frac{0}{-126} =0 $
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