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6/x=8/2x+1
We move all terms to the left:
6/x-(8/2x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+1)!=0We get rid of parentheses
x∈R
6/x-8/2x-1=0
We calculate fractions
12x/2x^2+(-8x)/2x^2-1=0
We multiply all the terms by the denominator
12x+(-8x)-1*2x^2=0
Wy multiply elements
-2x^2+12x+(-8x)=0
We get rid of parentheses
-2x^2+12x-8x=0
We add all the numbers together, and all the variables
-2x^2+4x=0
a = -2; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-2)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-2}=\frac{-8}{-4} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-2}=\frac{0}{-4} =0 $
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