6/x-4=x-3/x+2

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Solution for 6/x-4=x-3/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x-4 = x-(3/x)+2 // - x-(3/x)+2

6/x-x+3/x-4-2 = 0

9*x^-1-1*x^1-6*x^0 = 0

(9*x^0-1*x^2-6*x^1)/(x^1) = 0 // * x^2

x^1*(9*x^0-1*x^2-6*x^1) = 0

x^1

9-x^2-6*x = 0

9-x^2-6*x = 0

DELTA = (-6)^2-(-1*4*9)

DELTA = 72

DELTA > 0

x = (72^(1/2)+6)/(-1*2) or x = (6-72^(1/2))/(-1*2)

x = (6*2^(1/2)+6)/(-2) or x = (6-6*2^(1/2))/(-2)

x in { (6*2^(1/2)+6)/(-2), (6-6*2^(1/2))/(-2)} 

x in { (6*2^(1/2)+6)/(-2), (6-6*2^(1/2))/(-2) }

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