6/x+5/2x-7/8=-3

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Solution for 6/x+5/2x-7/8=-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x+6/x-(7/8) = -3 // + 3

(5/2)*x+6/x-(7/8)+3 = 0

(5/2)*x+6/x-7/8+3 = 0

5/2*x^1+6*x^-1+17/8*x^0 = 0

(5/2*x^2+17/8*x^1+6*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2+17/8*x^1+6*x^0) = 0

x^1

(5/2)*x^2+(17/8)*x+6 = 0

(5/2)*x^2+(17/8)*x+6 = 0

DELTA = (17/8)^2-(4*6*(5/2))

DELTA = -3551/64

DELTA < 0

x in { } 

x belongs to the empty set

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