6/x+2/x=8/x+1/3

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Solution for 6/x+2/x=8/x+1/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x+2/x = 8/x+1/3 // - 8/x+1/3

6/x+2/x-(8/x)-(1/3) = 0

6/x+2/x-8*x^-1-1/3 = 0

-1/3 = 0

x belongs to the empty set

x belongs to the empty set

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