6/v+5=-(1/2v+10)+4

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Solution for 6/v+5=-(1/2v+10)+4 equation:


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

6/v+5 = 4-((1/2)*v)-10 // - 4-((1/2)*v)-10

(1/2)*v+6/v-4+5+10 = 0

1/2*v^1+6*v^-1+11*v^0 = 0

(1/2*v^2+11*v^1+6*v^0)/(v^1) = 0 // * v^2

v^1*(1/2*v^2+11*v^1+6*v^0) = 0

v^1

(1/2)*v^2+11*v+6 = 0

(1/2)*v^2+11*v+6 = 0

DELTA = 11^2-(4*6*(1/2))

DELTA = 109

DELTA > 0

v = (109^(1/2)-11)/(2*(1/2)) or v = (-109^(1/2)-11)/(2*(1/2))

v = 109^(1/2)-11 or v = -(109^(1/2)+11)

v in { -(109^(1/2)+11), 109^(1/2)-11}

v in { -(109^(1/2)+11), 109^(1/2)-11 }

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