6/v+2=(-7/2v+4)+4

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Solution for 6/v+2=(-7/2v+4)+4 equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

6/v+2 = (-7/2)*v+4+4 // - (-7/2)*v+4+4

6/v-((-7/2)*v)-4-4+2 = 0

(7/2)*v+6/v-4-4+2 = 0

7/2*v^1+6*v^-1-6*v^0 = 0

(7/2*v^2-6*v^1+6*v^0)/(v^1) = 0 // * v^2

v^1*(7/2*v^2-6*v^1+6*v^0) = 0

v^1

(7/2)*v^2-6*v+6 = 0

(7/2)*v^2-6*v+6 = 0

DELTA = (-6)^2-(4*6*(7/2))

DELTA = -48

DELTA < 0

v in { } 

v belongs to the empty set

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