6/8a+6=3/4a

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Solution for 6/8a+6=3/4a equation: 



6/8a+6=3/4a

We move all terms to the left:

6/8a+6-(3/4a)=0



Domain of the equation: 8a!=0

a!=0/8

a!=0

a∈R





Domain of the equation: 4a)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

6/8a-(+3/4a)+6=0

We get rid of parentheses

6/8a-3/4a+6=0

We calculate fractions


24a/32a^2+(-24a)/32a^2+6=0

We multiply all the terms by the denominator


24a+(-24a)+6*32a^2=0

Wy multiply elements

192a^2+24a+(-24a)=0

We get rid of parentheses

192a^2+24a-24a=0

We add all the numbers together, and all the variables

192a^2=0

a = 192; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·192·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{384}=0$

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