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6/5a=2a
We move all terms to the left:
6/5a-(2a)=0
Domain of the equation: 5a!=0We add all the numbers together, and all the variables
a!=0/5
a!=0
a∈R
-2a+6/5a=0
We multiply all the terms by the denominator
-2a*5a+6=0
Wy multiply elements
-10a^2+6=0
a = -10; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-10)·6
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-10}=\frac{0-4\sqrt{15}}{-20} =-\frac{4\sqrt{15}}{-20} =-\frac{\sqrt{15}}{-5} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-10}=\frac{0+4\sqrt{15}}{-20} =\frac{4\sqrt{15}}{-20} =\frac{\sqrt{15}}{-5} $
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